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A train is moving at 65.0 m/s. After 16.0 seconds, it is moving at 85.0 m/s. What is the acceleration?

A train is moving at 65.0 m/s. After 16.0 seconds, it is moving at 85.0 m/s. What-example-1
User Robot
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2 Answers

4 votes

Answer:

Hope it will help you...

A train is moving at 65.0 m/s. After 16.0 seconds, it is moving at 85.0 m/s. What-example-1
User AbhinayMe
by
6.0k points
5 votes

Happy Holidays!

We can use the following equation to calculate uniform acceleration:


\large\boxed{a = (\Delta v)/(\Delta t) = (v_f - v_i)/(\Delta t)}}

Plug in the given values to solve:


(85 - 65)/(16)}} = (20)/(16) = \boxed{1.25 m/s^2}}

User SeungwooLee
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4.6k points
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