Question

Consider the proof. Given: segment ab is parallel to line de. Prove:startfraction a d over d c endfraction = startfraction b e over e c endfraction triangle a b c is cut by line d e. Line d e goes through side a c and side b c. Lines a b and d e are parallel. Angle b a c is 1, angle a b c is 2, angle e d c is 3, and angle d e c is 4. A table showing statements and reasons for the proof is shown. What is the missing statement in step 5? ac = bc startfraction a c over d c endfraction = startfraction b c over e c endfraction ad = be startfraction a d over d c endfraction = startfraction b e over e c endfraction.

Answer 1

B. or AC/BC = BC/EC

Step-by-step explanation:

Got it right on my test. Ed 2022 Would show work but laptop doesn't have camera. Sorry but this answer is correct.

Answer 2

Consider the proof. Given: segment ab is parallel to line de. Prove:startfraction a d over d c endfraction = startfraction b e over e c endfraction triangle a b c is cut by line d e. Line d e goes through side a c and side b c. Lines a b and d e are parallel. Angle b a c is 1, angle a b c is 2, angle e d c is 3, and angle d e c is 4. A table showing statements and reasons for the proof is shown. What is the missing statement in step 5? ac = bc startfraction a c over d c endfraction = startfraction b c over e c endfraction ad = be startfraction a d over d c endfraction = startfraction b e over e c endfraction.