Question

. A teacher pushes a desk across the floor for a distance of 5 meters. She exerted a horizontal force of 20N. How much work was done?

Answer 1

• Force (F) = 20 N
• Distance (s) = 5 m
• Angle between the force and distance (Θ) = 0°
• We know, work done = Fs Cos Θ
• Therefore, the work done by the teacher
• = (20 × 5 × Cos 0°) J
• = (20 × 5 × 1) J
• = 100 J

Answer:

100 J work was done.

Hope you could get an idea from here.

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