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Fx=x^2-2x+8
I need some help with this math problem if you can give me the process

User Faro
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1 Answer

6 votes

Answer:

x³/3 - x² + C

Explanation:

∫ x² - 2x + 8 dx

= x³/3 - x² + C

when finding the derivative, you need to take the power plus 1 then divide by the power x^(2+1)/(2+1) = x³/3

the same goes for 2x and the 2/2 is 1 so you would get x²

since you are finding the derivative for x and 8 is a constant it equals zero.

when integrating you always need to add C at the end and C stands for a constant. The only time you do not add C is when the integral goes from one constant to the next.

Example:
\int\limits^1_0 {x^2 - 3x +9} \, dx like this...

PLEASE RATE!! I hope this helps!!

If you have any questions comment below

User Kseniya
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