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Let f(x)=root2x. If the rate of change of f at x=c is four times its rate of change at x=1 then c=?

User Yanik
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1 Answer

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Answer:


c=(1)/(16)

Explanation:


f(x)=√(2x)


f'(x)=(√(2x))/(2x)


f'(1)=(√(2))/(2)


f'(c)=(√(2c))/(2c)


f'(c)=4f'(1)


(√(2c))/(2c)=4((√(2))/(2))


(√(2c))/(2c)=2√(2)


√(2c)=4c√(2)


2c=32c^2


2=32c


(1)/(16)=c

User Guy Levin
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