Question

A man has 25 sweets and his son has 55 sweets.find the number of sweets that the man has to give to his son so that his son would have 4times as many sweets as him.

Answer 1

9sweets

Explanation:

sweets man has to give to his son=x

mans sweets=25-x

child's sweets=55=x

55+x=4(25-x)

55+x=100-4x

4x+x=100-55

5x=45

x=45/5

x=9

Answer: The man has to give nine sweets for his son to have four times as many sweets as him.

Answer 2

Sweets man has to give is x
Man's sweets = 25 - x
The boy's sweets = 55 + x
This number is 4 times

55 + x = 4(25 - x)
55 + x = 100 - 4x
55 - 100 = -4x - x
-45 = - 5x
45 ÷ 5 = x
6.67 = x
6.67 ≈ 7
the man gives 7 sweets to the son so the son would have 4 times as much as the father