146k views
0 votes
The length of a rectangle is 5 yd less than three times the width, and the area of the rectangle is 50 yd. Find the dimensions of the rectangle.

User Inesa
by
6.9k points

1 Answer

5 votes

Final answer:

To solve for the dimensions of the rectangle, represent the width as w, forming the equation 50 = (3w - 5)w. The resulting quadratic equation is solved to obtain the width w, and subsequently the length using 3w - 5.

Step-by-step explanation:

The question asks us to find the dimensions of a rectangle given that the length is 5 yards less than three times the width and that the area of the rectangle is 50 square yards. Let w represent the width of the rectangle. Then the length l will be 3w - 5. To find the area (A) of a rectangle, we use the formula A = l × w. We know the area is 50 square yards, so we can set up the equation 50 = (3w - 5)w.

Solving for w, we get a quadratic equation: 3w^2 - 5w - 50 = 0. We can solve for w by factoring or using the quadratic formula. Once we find w, we can use it to calculate l as 3w - 5.

Finding the exact values will involve factoring the quadratic equation or using an alternative method like completing the square or utilizing the quadratic formula.

User Shda
by
8.4k points

No related questions found