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Knowing that the solubility of a salt at 80°C is 45g/100 g of H,O, calculate the mass of water required for dissolve 250 g of this salt at 80º C.​

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The mass of water required will be approximately
\bf = 555.6\: g.

  • To solve this question, just make a simple rule of three between the amount of salt dissolved at 80ºC and the mass of water:


\qquad 45g of salt
\sf \longrightarrow 100g of H₂O


\qquad 250g of salt
\sf \longrightarrow x g of H₂O


\qquad
\red{\twoheadrightarrow\bf45* x = 250* 100}


\qquad
\twoheadrightarrow\sf45x=25000


\qquad
\twoheadrightarrow\sf x=\cancel{(25000)/(45)}


\qquad
\red{\twoheadrightarrow\bf x = 555.6\:g}

  • Therefore, knowing that the solubility of a salt at 80ºC is 45g/100g of water (H₂O), the mass of water needed to dissolve 250g of this salt at 80ºC will be
    \red{\bf = 555.6\: g }

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