Question

thirty tickets were sold for a concert, some at 60 cent and the rest is at $1. If the total was raised to $22, how many had the cheaper tickets.

Answer 1

20

Explanation:

To solve this question we can use a system of linear equations. The 2 equations should represent- 1) the number of total tickets sold and 2) the total amount raised. So, the two equations look like this (in this situation, let x stand for the cheaper tickets and y for the more expensive ones).

• x+y=30
• 0.6x+1y=22

Then, there are multiple ways to solve this including graphing, elimination, and substitution. In my opinion, substitution is the best for this situation.

Firstly, isolate the y variable in the first equation

• y=30-x

Next, plug in this value for y in the second equation

• 0.6x+(30-x)=22

Then, solve this equation algebraically

• x=20

Since x stands for the cheaper tickets, we know that 20 people bought the cheaper tickets.