Question

Can someone please help me, i need the help?

Answer 1

`f(x)/ g(x)=-10`

Explanation:

Solve
`f(x)`

`f(x)=x^2-19x+90`

`x^2-19x+90`

`\mathrm{Break\:the\:expression\:into\:groups}`

`\left(x^2-9x\right)+\left(-10x+90\right)`

`\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2-9x`

`=x(x-9)`

`\mathrm{Factor\:out\:-10\;from}\:\:-10x+90`

`=-10(x-9)`

`=x\left(x-9\right)-10\left(x-9\right)`

`\mathrm{Factor\:out\:common\:term\:}x-9`

`\bold{\left(x-9\right)\left(x-10\right)}`

Solve
`g(x)`

`g(x)=x-9`

`\bold{x-9}`

`(x-9\right)\left(x-10)}/ \:x-9`

Now, solve:

`(x-9\right)\left(x-10)}/ \:x-9`

`=((x-9)\left(x-10))/(:x-9)`

`= -10`

Therefore,
`f(x)/ g(x)=-10`

Answer 2

`f(x)/ g(x)=x-10`

Explanation:

`(x^2-19x+90)/(x-9)`

`((x-10)(x-9))/(x-9)`

`x-10`