the value of the difference r-s is

Answer:
Solution given:
(3x+14)x=5
opening bracket
3x²+14x=5
3x²+14x-5=0
Doing middle term factorisation
3x²+(15-1)x-5=0
3x²+15x-x-5=0
3x(x+5)-1(x+5)=0
(3x-1)(x+5)=0
either
x=-5
or
3x-1=0
3x=1
x=⅓
According to question value of x is r>s
so
⅓>-5
so
r=⅓
and
s=-5
Now
r-s=⅓-(-5)=
