Question

A certain space heater that is connected across 220 V and dissipates 1477 W of power in the form of electromagnetic radiation. What is the resistance of the heater?

Answer 1

Hi there!

We can use the power equation:

`P = (V^2)/(R)`

P = Power (W)
V = Potential Difference (V)
R = Resistance (Ω)

Rearrange to solve for Resistance:

`R = (V^2)/(P) = (220^2)/(1477) = \boxed{32.769 \Omega}`