Question

In 2000, the moose population in a park was measured to be 650. By 2010, the population was measured to be 750. Assume the population continues to change exponentially. Find a formula for the moose population, P(x), where x is the number of years after 2000

Answer 1

650 * (1.01)ˣ = P(x)

Explanation:

One formula for exponential growth is

a*bˣ, where x represents time, a represents the initial amount, and b represents the growth rate. We have 650 as our initial amount because x is the number of years after 2000, and there are 650 moose in 2000. Then, we have

650 * b¹⁰ = 750 because, after 10 years, the moose population is 750. Solving for b, we have

750/650 = b¹⁰

(750/650)^(1/10) = b

= 1.01441296377 (can round this to 1.01)

Therefore, after x years, the moose population can be represented by the equation

650 * (1.01)ˣ