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Find n. (n!)²- 4n! - 12 = 0​

User Yujingz
by
7.9k points

1 Answer

1 vote

Answer:

n=6 , n=-2

Explanation:


n^(2)-4n-12=0

Factorise to give:


(n-6)(n+2)

Set first one to equal 0:


n-6=0


n=6

Set second one to equal 0:


n+2=0


n=-2

Reason for 2 solutions:

All quadratics can have a maximum of 2 solutions like this one or a minimum of 0.

The solution(s) is the point where the graph crosses the x-axis

The image below shows the graph of the equation:


n^(2)-4n-12

When y=0:

It intercepts the x-axis at 6 and -2 giving why n has 2 solutions

Find n. (n!)²- 4n! - 12 = 0​-example-1
User Levine
by
7.6k points

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