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Suraj took a slice of pizza from the freezer and put it in the oven. The pizza’s temperature (in degrees celsius) as a function of time (in minutes) is graphed. What was the pizza’s temperature after 2 minutes?

1 Answer

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For this case, the first thing we should do is write the linear function that best suits the table.

In this case we have the following function:

y = 7.5x - 5

C = 7.5t-5

For C = 100 we have:

100 = 7.5t-5

We clear the time:

t = (100 + 5) / (7.5)

t = 14

Answer:

it did take the pizza to reach 100 degrees Celsius about 14 minutes

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