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Which of the following is ''NOT'' a factor of x3 – 3x2 – 4x + 12?

A) (x + 3)
B) (x – 3)
C) (x – 2)
D) (x + 2)

User Ranjith
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1 Answer

3 votes

Answer: A) x+3

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Step-by-step explanation:

We can use the special case of the remainder theorem, aka the factor theorem, which says:

If p(k) = 0, then x-k is a factor of p(x).

For choice A, we have x-k = x+3 = x-(-3) to show that k = -3

Plug that k value into the given expression

x^3 - 3x^2 - 4x + 12

(-3)^3 - 3(-3)^2 - 4(-3) + 12

-30

We don't get 0 which means x+3 is not a factor of the expression above. Therefore, choice A is the final answer.

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If we tried something like choice B, then k = 3 leads us to...

x^3 - 3x^2 - 4x + 12

(3)^3 - 3(3)^2 - 4(3) + 12

0

which points us to (x-3) being a factor of the original expression. The same happens with choices C and D as well. This allows us to rule out choices B, C and D.

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A quick alternative is to graph x^3 - 3x^2 - 4x + 12 using software like Desmos or GeoGebra. I posted the graph below. The graph shows that the roots are x = 3, x = 2, x = -2. Those roots mentioned lead to factors x-3, x-2, x+2 in that order (which correspond to choices B,C,D in the same order).

In short, the roots tell us the factors fairly quickly, which allows us to cross off the non-answers.

Which of the following is ''NOT'' a factor of x3 – 3x2 – 4x + 12? A) (x + 3) B) (x-example-1
User Pkt
by
4.4k points