Question

If x=2, y=4, m= -1, and n=3 find the value of :
X^m+n * y^n-m/ x^m-n * y^n+m

Answer 1

The value is
`(1)/(16384)`

Explanation:

Here we need to find

`(x^(m+n)\cdot y^(n-m))/(x^(m-n)\cdot y^(n+m))=x^(m+n-(m-n))\cdot y^(n-m-(n+m))\\\\=x^(2n)\cdot y^(-2m)\\\\=2^(2\cdot-1)\cdot 4^(-2\cdot3)\\\\=(1)/(2^2*4^6) \\\\=(1)/(16384)`