Question

What is the equation of a line that contains points (5,3) and (0, -1)

Answer 1

y =
`(4)/(5)` x - 1

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m =
`(y_(2)-y_(1) )/(x_(2)-x_(1) )`

with (x₁, y₁ ) = (5, 3 ) and (x₂, y₂ ) = (0, - 1 )

m =
`(-1-3)/(0-5)` =
`(-4)/(-5)` =
`(4)/(5)`

The line crosses the y- axis at (0, - 1 ) ⇒ c = - 1

y =
`(4)/(5)` x - 1 ← equation of line