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i. a A ball is released from a height of 45 m top of the building. If it strikes the ground surface after 5 seconds, calculate the acceleration and final velocity of the ball. [18 m/s, 3.6 m/s²].​
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i. a A ball is released from a height of 45 m top of the building. If it strikes the ground surface after 5 seconds, calculate the acceleration and final velocity of the ball. [18 m/s, 3.6 m/s²].​

User Cmann
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1 Answer

5 votes

Answer:

3.6m/s², 18m/s

Step-by-step explanation:

So according to h=1/2at², 45=1/2a*25, a=3.6m/s² (which means that it didn't happen on Earth?)

Final velocity = at = 3.6*5 = 18 m/s

User Ezzatron
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