Answer:
Step-by-step explanation:
ASSUMING that the dart is fired horizontally so that gravity potential energy considerations are not needed. Also ignoring friction work.
The spring potential will convert to kinetic.
KE = PS
½mv² = ½kx²
v =
![√(kx^2/m)](https://img.qammunity.org/2022/formulas/physics/college/hszkzq6464qj9vmf456j59n68c9s1ksn3r.png)
v =
![√(1115(0.05^2)/0.025)](https://img.qammunity.org/2022/formulas/physics/college/wh21mwhxli29p3htxlhstjjv5w3bhz747j.png)
v = 10.55935...
v = 11 m/s