Question

write an equation of the line passing through the point (5,2) that is perpendicular to the line "-x+3y=12"

Answer 1

y = -3x + 17

Explanation:

first, change the equation into slope-intercept form

add 'x' to each side to get:

3y + x = 12

divide each side by 3 to get:

y = 1/3x + 4

now we need to use a slope that is the opposite reciprocal of 1/3 which would be -3, in conjunction with the point (5,2), by entering these values into the slope-intercept form so we can find the y-intercept ('b') of the new line:

2 = -3(5) + b

2 = -15 + b

17 = b

put slope and y-intercept together to get:

y = -3x + 17