Question

Find an equation of a line through (2,-5), perpendicular to 3y=x-6. Write in function notation. ANSWER FAST PLS

Answer 1

Equation of perpendicular line

`\\ \sf\dashrightarrow 3y=x-6`

`\\ \sf\dashrightarrow y=(1)/(3)x-2`

Comparing with y=mx+b

• m=1/3

Slope of perpendicular line=-3

Passing through (2,-5)

Equation of line in point slope form

`\\ \sf\dashrightarrow y-y_1=m(x-x_1)`

`\\ \sf\dashrightarrow y+5=-3(x-2)`

`\\ \sf\dashrightarrow y+5=-x+6`

`\\ \sf\dashrightarrow x+y-1=0`