Question:-

We need to solve the inequality.
Solution:-

We need to exchange ≥ to equal ( = )sign to solve Further.

Add 16 to both sides of this equation :-

On Simplification of this equation:-


Then Take the square root of 36:-

On Simplification :-

Then,
Check the interim in between two points.
So for this, Replace x = 6 to x ≥ 6 and x = -6 to x ≤ - 6.This is the solution of this question.

And,

Option D
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Henceforth,The Answer is :-


Option D is the correct answer
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I hope this helps!
Please let me know if you have any questions.
~MisterBrian