Answer:
2 < y < 6
Explanation:
Expand the brackets, multiplying by y
12 < 8y - y^2
Rearrange
0 < -y^2 + 8y - 12
Divide by -1. When dividing by a negative number, you must flip the inequality sign
0 > y^2 - 8y + 12
Factorise
0 > (y - 6)(y - 2)
The two solutions are y = 6, 2
Check using a value inbetween 2 and 6 to see if the inequality holds true. For example 3 is between 2 and 6
0 > (3 - 6)(3 - 2)
0 > -3(1)
0 > -3
As this holds true, this means that y lies between 2 and 6
Therefore, the answer is 2 < y < 6
(If the inequality did not hold true, then y would lie above 6 and below 2. y < 2 and y > 6. Not relevant for this example)