Explanation:
The given equation is 12x2+4kx+3=0
Here, a=12,b=4k,c=3
∴D=b2−4ac=(4k)2−4×12×3=16k2−144
The given equation will have real and equal roots, if
D=0⇒16k2−144=0⇒k2=9⇒k=±3
hope it helps
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