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The lines shown below are perpendicular.

5
(-2,4)
4
(2.1)
5
(0,-2)
(-4,-2)
A. True
B. False

The lines shown below are perpendicular. 5 (-2,4) 4 (2.1) 5 (0,-2) (-4,-2) A. True-example-1
User Timmy Lin
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Answer:

False. The two lines in this diagram are not perpendicular with one another.

Explanation:

Two lines in a plane are perpendicular if and only the product of their slopes is
(-1).

If a non-vertical line in a plane goes through two points,
(x_(0),\, y_(0)) and
(x_(1),\, y_(1)) (
x_(0) \\e y_(0),) the slope of this line would be:


\begin{aligned}m &= (y_(0) - y_(1))/(x_(0) - x_(1))\end{aligned}.

Find the slope of the two lines given the coordinates of the points.

Slope of the line sloping downwards:


\begin{aligned}m_(a) &= (4 - (-2))/((-2) - 0) \\ &= (6)/((-2)) \\ &= (-3)\end{aligned}.

Slope of the line sloping upwards:


\begin{aligned}m_(b) &= (1 - (-2))/(2 - (-4)) \\ &= (3)/(6) \\ &= (1)/(2)\end{aligned}.

The product of the slopes of the two lines is:


\begin{aligned}m_(a)\, m_(b) &= (-3) * (1)/(2) \\ &= \left(-(3)/(2)\right)\end{aligned}.

Therefore, these two lines are not perpendicular to one another since the product of their slopes isn't
(-1).

User Holydragon
by
8.4k points

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