Question

`\huge \dag \sf{Answer \: it}`​


`f = g * \frac{m _(1)m_(2)}{ {d}^(2) }`
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Answer 1

Hey There!

Let's solve ....

`let \: m_(1) \: and \: m_(2) \: are \: the \: two \\ masses \: seperated \: by \: \\ distance \: d \\ \\ lets \: find \: equation \: 1 \\ \\ f \propto m_(1) m_(2) \\ \\ now \: equation \: 2 \\ \\ f \propto \frac{1}{ {d}^(2) }`

On combining these two equations, it comes

`f \propto \frac{ m_(1) m_(2) }{ {d}^(2) } \\ \\ f = g * \frac{ m_(1) m_(2) }{ {d}^(2) } \\ \\`

[G is a gravitational constant here]...

Hence it is proved.

I hope it is helpful to you..

Cheers!_________