Answer:
Explanation:
Question 5: x = 17
The question is x - 3 = 14
Your goal is to isolate the variable, x, on its side of the equation. To do that, you must first reverse the operation -3, or minus 3, by using addition
**Doing that is called using the inverse operation
x - 3 = 14
x -3(+3) = 14
x = 14
But what you do to one side of the operation, you have to do to the other
x = 14
x = 14(+3)
x = 17
If you insert 17 into the original equation:
17 - 3 = 14
Question 6: x = 2.3
3.5 = m + 1.2
Your goal is to isolate the variable, m, on its side of the equation. To do that, you must first reverse the operation + 1.2, or plus 1.2, by using subtraction
3.5 = m + 1.2
3.5 = m + 1.2 (-1.2)
3.5 = m
But what you do to one side of the operation, you have to do to the other
3.5 = m
3.5 (- 1.2) = m
2.3 = m
If you insert 2.3 into the original equation:
3.5 = 2.3 + 1.2
Question 7: b = 3 2/3
b + 2/3 = 4 1/3
Your goal is to isolate the variable, b, on its side of the equation. To do that, you must first reverse the operation + 2/3, or plus 2/3, by using subtraction.
b + 2/3 = 4 1/3
b + 2/3 (-2/3) = 4 1/3
b = 4 1/3
But what you do to one side of the operation, you have to do to the other
b = 4 1/3
b = 4 1/3 (-2/3)
b = 3 2/3
If you insert 3 2/3 into the original equation:
3 2/3 + 2/3 = 4 1/3
Question 8: x = 17.6
x - 11.4 = 6.2
x - 11.4 (+ 11.4) = 6.2
x = 6.2
x = 6.2 (+ 11.4)
x = 17.6
If you insert 17.6 into the original equation:
17.6 - 11.4 = 6.2
Question 9: x = 4
15x = 60
Your first goal is to isolate the variable, x, on its side of the equation. To do that, you must first reverse the operation 15x, or 15 times x, by using division.
15x = 60
15x (÷ 15) = 60
***Notice: I am dividing 15x by only 15 (without the variable)
x = 60
But what you do to one side of the operation, you have to do to the other
x = 60
x = 60 (÷ 15)
x = 4
If you insert 4 into the original equation:
15(4) = 60
Question 10: y = 8
9.6 = 1.2y
Your first goal is to isolate the variable, y, on its side of the equation. To do that, you must first reverse the operation 1.2y, or 1.2 times y, by using division.
9.6 = 1.2y
9.6 = 1.2y (÷ 1.2)
**Notice: I am dividing 1.2y by only 1.2 (without the variable)
9.6 = y
But what you do to one side of the equation, you have to do to the other
9.6 = y
9.6 (÷ 1.2 )= y
8 = y
If you insert 8 into the original equation:
9.6 = 1.2(8)
Question 11: x = -9.6
-2.4 = x/4
Your first goal is to isolate the variable, x, on its side of the equation. To do that, you must first reverse the operation x/4, or x divided by 4, by using multiplication.
-2.4 = x/4
-2.4 = x/4 (4)
Notice: I am multiplying x/4 (x divided by 4) by only 4
-2.4 = x
But what you do to one side of the equation, you have to do to the other.
-2.4 = x
-2.4 (4) = x
-9.6 = x
If you insert the answer -9.6 into the original equation:
-2.4 = -9.6/4
Question 12: m = 48
1/8m = 6
Your first goal is to isolate the variable, m, on its side of the equation. To do that, you must first reverse the operation 1/8m, or 1 divided by 8 times 4, by using multiplication.
****Understand that equations such as 1/8m are division problems, not multiplication.
1/8m = 6
1/8m (x 8) = 6
***Notice that I am multiplying 1/8m by 8. When you see these types of problems, make sure to multiply by the reciprocal (and never include the variable!!)
m = 6
But what you do to one side of the equation, you have to do to the other
m = 6
m = 6 (8)
m = 48
If you insert 48 into the original equation:
1/8 (48) = 6