Question

Richard and Teo have a combined age of 21. Richard is 3 years older than twice Teo’s age. How old are Richard and Teo?

Answer 1

Richard's age = 15

Teo's age = 6

Explanation:

Let's say Teo's age is x.

Then, we will get this very equation.

`3 + 2x`

The equation above is Richard's age.

`x + 2x + 3 = 21`

This equation is their ages conbined.

Now, let's solve the equation.

Collect like terms.

`3x + 3 = 21`

Move the constant. ( Which is 3, in this case. )

`3x = 21 - 3`

Calculate.

`3x = 18`

Because we want only "x", divide both sides of the equation by 3.

`x = 6`

As I have said above, "x" is Teo's age.

Let's find Richard's.

It is:

2x + 3

x is 6.

(2 x 6) + 3

12 + 3

15 ( Richard's age.)

I hope it helps.

Answer 2

• Two's age = 6 years.
• Richard's age = 15 years

Explanation:

In the question ,

Given :

• Richard and Two have combined age of 21.

• Richard is 3 years older than twice Two's age

And , we have to find the ages of Richard and Teo . So we are assuming that Teo's age be x . Therefore Richard's age be 2x + 3 ( because in the question it is given that Richard is 3 years older than twice the age of Teo ) .

According to question , we are adding Richard's age and Teo's age :

`\longrightarrow \: x + 2x + 3 = 21`

Step 1 : Adding the like term in left hand side :

`\longrightarrow \: 3x + 3 = 21`

Step 2 : Transposing 3 to right hand side :

`\longrightarrow \: 3x = 21 - 3`

Step 3 : By Subtracting 3 from 21 , We get :

`\longrightarrow \: 3x = 18`

Step 4 : Transposing 3 to right hand side :

`\longrightarrow \: x = \cancel(18)/(3)`

Step 5 : Now dividing 18 by 3 :

`\longrightarrow \: \red{\boxed{ x = 6}}`

We know that ,

• x = Teo's age
• 6

• Therefore , Teo's age is 6 year old .

And ,

• 2x + 3 = Richard's age
• 2 ( 6 ) + 3
• 12 + 3
• 15

• Therefore , Richard's is 15 year old

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