Question

An object was measured by a worker as

17.400 cm long, however, the manufacturer
specifications list the length of the object
at 17.900 cm. What is the percent error in
the worker's measurement?
a. 2.79% or b. 2.87%

Answer 1

2.79 % error

Step-by-step explanation:

Percent Error = 100 x [(Actual - Measured) / Actual]

Percent Error = 100 x [(17.900 - 14.700) / 17.900]

Percent Error = 100 x [0.5 / 17.900]

Percent Error = 100 x 0.02793

Percent Error = 2.7932 % or 2.79 %