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Find the equation of the line that is parallel to 4y-x=3 and passes through the point (8,-7)

User Steven
by
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1 Answer

6 votes

Answer:

y=x/4 - 9

Explanation:

4y-x=3

y=1/4x +3/4

G1=1/4

at parallel G1 =G2

so G2 =1/4

y+7 /x-8 =1/4

4y + 28 = x - 8

4y = x-8-28

4y =×-36

y =1/4x -9

User Wubblyjuggly
by
8.1k points

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