Question

A 5 kg block is being pushed horizontally across a level surface at a constant velocity. What is the magnitude of the Normal force acting on the block?

Hint: strength of gravity is 10 N/kg

Answer 1

50 N.

Step-by-step explanation:

On top of a horizontal surface, the normal force acting on an object is equivalent to the force of gravity acting on the object. That is:

`\displaystyle \begin{aligned} F_N = F_g & = ma \\ & = mg\end{aligned}`

The mass of the block is 5 kg and the given force due to gravity is 10 N/kg. Substitute and evaluate:

`\displaystyle F_N = F_g = (5\text{ kg})(10 \text{ N/kg}) = 50 \text{ N}`

In conclusion, the normal force acting on the block is 50 N.