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5x + 3y = 41
2x + 3y = 20
show me step by steps how to do this

2 Answers

4 votes

Answer:

Explanation:

It looks like you need to solve this system of equations.

That means we need to find a value for x and a value for y that makes both equations true.

Since both equations have a 3y in them, this system is ready to use a method called "elimination method"

Since the x terms are lined up, and the y terms are lined up, the equal signs are lined up, and the constants are lined up...you can subtract the bottom equation from the top equation.

5x + 3y = 41

2x + 3y = 20

Subtract and you will get

3x + 0y =21

We don't need to write that 0y, because it is 0.

3x = 21, now divide by 3

x = 7, almost finished!

Use x = 7 in either of the original equations to find y.

5x + 3y = 41 and x = 7

5•7+ 3y = 41

35 + 3y = 41

-35 -35

3y =6

y = 2

So the solution is x=7 and y=2

That can also be written as an ordered pair (7, 2)

User Tafaust
by
7.8k points
6 votes

Answer:

The answers are:

  • x = 7
  • y = 2

Explanation:

5x + 3y = 41

2x + 3y = 20

  • => 5x + 3y = 41

-2x - 3y = -20

  • => 3x = 21
  • => x = 7

  • => 5(7) + 3y = 41

  • => 35 + 3y = 41

  • => 3y = 41 - 35

  • => 3y = 6

  • => y = 2

Conclusion:

Therefore, the answers are:

  • x = 7
  • y = 2

Hoped this helped


-BrainiacUser1357-

User TonyB
by
8.6k points

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