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NEED HELP ASAP PLEASE The drop time can be calculated as follows t = sqrt((2y)/g) where y is the vertical height of the table and g is the acceleration due to gravity (9.80 m/)How did the calculated drop
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NEED HELP ASAP PLEASE

The drop time can be calculated as follows t = sqrt((2y)/g) where y is the vertical height of the table and g is the acceleration due to gravity (9.80 m/)How did the calculated drop time compare to the average of your measured drop times? Find the percent error using the following equation measured drop time - calculated drop time % 100 calculated drop time What factors might cause the differences?

NEED HELP ASAP PLEASE The drop time can be calculated as follows t = sqrt((2y)/g) where-example-1
User Cobbal
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2 Answers

5 votes

Answer:

I would think human error could cause differences like not pressing the stop watch on time.

Step-by-step explanation:

User Vivek Raskar
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5.4k points
4 votes

did you end up getting the answer- im struggling

User Max De Marzi
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