Question

PLEAS HELP

A scuba diver descends in the water at a rate of 2312 feet per minute for 2.6 minutes. He immediately changes course when he sees a large fish and ascends at a rate of 28 feet per minute for 2 minutes.


What is the scuba diver's position relative to sea level after the 4.6 minutes?


Enter your answer as a decimal in the box.


ft

Answer 1

2312 FPM for 2.6 minutes

2312 x 2.6 = 6011.2

28 FPM for 2 minutes

28 x 2 = 56

6011.2 descend

55 ascend

0-6011.2 = -6011.2

ans + 56 = -5955.2

:)

Answer 2

Descends: 2,312 x 2.6 = - 6,011 (when rounding otherwise known as - 6,011.2, this number is negative because he is descending)

Ascends: 28 x 2 = 56

- 6,011 + 56 = -5,955 (in 4.6 minutes)

Explanation:

I believe this is the correct answer, I'm not 100% sure though. Please tell me if I'm wrong. Have a wonderful rest of your day or night! ~ ^w^ ~