Question

Given an unknown metal using C= {Q/(M T)} with energy added of 8,000. J, in which the temperature goes from 24.0 C to 28.0 C at a mass of 46.0 g, find its specific heat capacity?​

Answer 1

47.48 J/g/K or 4.74 × 10⁴J/Kg/K

Step-by-step explanation:

C(specific heat capacity)= Q(quantity of heat)/M(mass) × ∆T(change in temperature, Kelvin)

Q= 8000J

M= 46g or 46 ×10^-3Kg

T1= 24°C = 297K

T2 = 28°C = 301K

∆T = 301-297

= 4K

C= 8000/46 × 4

= 47.48 J/g/K or 4.74 × 10⁴J/Kg/K