Question

Ben (55kg) is standing on very slippery ice when Junior (25kg) bumps into him. Junior was moving at a speed of 8m/s before the collision. Find the speed of ben and junior as they move across the ice after the collision. Give the answer in m/s. Describe the work you did to get the answer

Answer 1

2.5m/s

Step-by-step explanation:

m1=55kg

m2=25kg

Ben's velocity before collision=0m/s

Junior's velocity before collision= 8m/s

P1=m1v1+m2v2

P1=55kg(0m/s)+25kg(8m/s)

P1=200kg(m/s)

Know that the momentum before the collision = momentum after the collision

P2=(55kg+25kg)V

200kg(m/s)=(75kg)V

200kg(m/s)/75kg=V

V=2.5m/s.

It makes sense bc after they collide, their speed would slow down, and it wouldn't make sense if the momentum would be greater or less after they collide.