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A 6.00 L container of N_2 has a temperature of 273 K. Calculate the volume if the temperature is doubled. a 24.0 L b 12.0 L c 6.0 L d 3.0 L
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A 6.00 L container of N_2 has a temperature of 273 K. Calculate the volume if the temperature is doubled.

a
24.0 L

b
12.0 L

c
6.0 L

d
3.0 L

User Sajith Vijesekara
by
5.9k points

1 Answer

6 votes
V1/T1 =V2/T2 (using charles law)

V1=6.00
V2=?
T1=273
T2=273

Making V2 the subject of formula the equation then becomes

V2= V1xT2/T1

6.00x263/273=6.0L
User Magd Kudama
by
6.7k points
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