Answer:
Explanation:
Assuming the density is the same for both lollipops, we can calculate what volume is required to make the 2158.7kg the same density of the smaller lollipop.
Small Lollipop
r = 2cm
V=4 /3πr^3
V = 33.51 cm^3
Mass is 50 g in 33.51 cm^3, so the density is:
50g/(33.51 cm^3) = 1.492 g/cm^3
We have 2158.7kg in the larger lollipop. That is 2158700 grams.
Find the volume required to contain 2158700 grams with a density of 1.492 g/cm^3. :
(2158700 grams)/(1.492 g/cm^3) = 1446775 cm^3
V=4 /3πr^3
1446775 cm^3 = (4/3)*π*r^3
r = 70.12 cm