Question

Find the equation of the line l that is perpendicular to -3x + 6y = 11 and I passes

through the point (-2, 3)

Answer 1

Explanation:

-3x + 6y = 11

Put into slope-intercept form to find the slope

6y = 3x + 11

y = 3x/6 + 11/6

y = ½x + 11/6

so slope is ½

perpendicular lines have negative reciprocal slopes, so our perpendicular line has slope -2

the slope point form of the perpendicular line will be

(y - 3) = -2(x -(-2))

(y - 3) = -2(x +2)

the slope intercept form will be

y = -2x - 4 + 3

y = -2x - 1