Question

Consider the following two linear equations 3x+3y=-3 "-3+2y=8"

Answer 1

`- 3 + 2y = 8`

`2y = 8 + 3`

`2y = 11`

`y = (11)/(2)`

Substitute y=11/2 in the first eq:

`3x + 3( (11)/(2) ) = - 3`

`3x = 3 - (33)/(2)`

`3x = (6 - 33)/(2)`

`3x = ( - 27)/(2)`

`x = ( - 27)/(6)`

Answer 2

Explanation:

3x + 3y = -3 ------------(I)

-3x + 2y = 8 -----------(II)

Add both the equations and x will be cancelled and we can find the value of y

(I) 3x + 3y = -3

(II) -3x + 2y = 8 {Now add}

5y = 5

y = 5/5

y = 1

Now, substitute y = 1 in any of the equations. We are going to substitute in equation (I)

3x + 3*1 = -3

3x + 3 = -3

3x = -3 - 3

3x = -6

x = -6/3

x = -2

The solution of the equation is the point of intersection.

Point of intersection = ( -2, 1)