Find the factors of f(x) given that x = −3 is a zero. f(x) = x^3 + 12x^2 + 47x + 60 (x + 3)(x + 4)(x − 5) (x + 3)(x + 4)(x + 5) (x − 3)(x + 5)(x + 6) (x + 3)(x + 3)(x − 3)

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asked Mar 8, 2022 135k views

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Find the factors of f(x) given that x = −3 is a zero.

f(x) = x^3 + 12x^2 + 47x + 60
(x + 3)(x + 4)(x − 5)
(x + 3)(x + 4)(x + 5)
(x − 3)(x + 5)(x + 6)
(x + 3)(x + 3)(x − 3)

Mathematics
high-school

Joseph Erickson asked

by Joseph Erickson

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$x^3+12x^2+47x+60\\\\=x^3+3x^2 +9x^2+27x+20x+60\\\\=x^2(x+3) + 9x(x+3)+20(x+3)\\\\=(x+3)(x^2+9x+20)\\\\=(x+3)(x^2 + 4x +5x +20)\\\\=(x+3)[x(x+4)+5(x+4)]\\\\=(x+3)(x+4)(x+5)$

Jon Betts answered Mar 13, 2022

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