Question

Find the distance, midpoint, and slope of line AB. A(-2,-1) and B(6,3)

Answer 1

`Slope (m) = (y)/(x)=(1)/(2) = 0.5`

`Distance (d) = √(x^2+y^2) =√(80) =8.9442719099992`

`Mindpoint =\left(2,\:1\right)`

Explanation:

`Slope (m) = (y)/(x)=(1)/(2) = 0.5`

`0 = arctan((y)/(x) = 26.565051177078^o`

`Distance (d) = √(x^2+y^2) =√(80) =8.9442719099992`

X = 6 – -2 = 8

Y = 3 – -1 = 4

Equation of the line:

y = 0.5x

When x=0, y = 0

When y=0, x = -0

Midpoint:

`\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left((x_2+x_1)/(2),\:\:(y_2+y_1)/(2)\right)`

`\left(x_1,\:y_1\right)=\left(-2,\:-1\right),\:\left(x_2,\:y_2\right)=\left(6,\:3\right)`

`=\left((6-2)/(2),\:(3-1)/(2)\right)`

`=\left(2,\:1\right)`