Final answer:
The cherry pit will hit the ground approximately 8.1 meters horizontally from the initial dropping point. A picture would depict the pit falling in projectile motion while the car moves at a constant speed. The car and the pit will be aligned horizontally when the pit lands.
Step-by-step explanation:
To solve for the distance a cherry pit dropped from a moving car covers horizontally, we'll use principles of projectile motion. Since the pit is dropped and not thrown, it has an initial vertical velocity of 0 m/s. However, it maintains the horizontal velocity of the car, which is 18 m/s. We need to calculate the time it takes for the pit to hit the ground, which is solely determined by its initial vertical motion and acceleration due to gravity (9.8 m/s2).
Using the kinematic equation d = Vi*t + 0.5*a*t2 where d is the vertical distance (1.0 m), Vi is the initial vertical velocity (0 m/s), a is the acceleration due to gravity (9.8 m/s2), and t is the time in seconds, we can solve for t.
0 = 1.0 m - 0.5*9.8 m/s2*t2, solving for t gives us approximately 0.45 seconds.
To find the horizontal distance, we multiply the time by the horizontal velocity: Distance = horizontal velocity * time = 18 m/s * 0.45 s ≈ 8.1 meters.
The picture would show a car moving to the right and the cherry pit falling directly down while also moving to the right at the same horizontal speed as the car.
Since the car is moving at the same constant speed, when the cherry pit hits the ground after 0.45 seconds, the car will be directly above the pit, having covered the same horizontal distance.