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Which equation could define the function below? y= (x+1)(x+ .5) (x+ 3.5) y= (x+1) (X - .5) (x-3.5) y = (x-1) (X-.5) (x-3.5) y= (x+1) (X- .5) (x +3.5)
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Which equation could define the function below?

y= (x+1)(x+ .5) (x+ 3.5)
y= (x+1) (X - .5) (x-3.5)
y = (x-1) (X-.5) (x-3.5)
y= (x+1) (X- .5) (x +3.5)

User Droidd
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1 Answer

2 votes

Answer:

y= (x+1)(x+ .5) (x+ 3.5)

y= (x+1) (X - .5) (x-3.5)

y = (x-1) (X-.5) (x-3.5)

y= (x+1) (X- .5) (x +3.5)

Explanation:

User Koiralo
by
4.4k points
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