Question

the sum of two numbers is 68. the larger number is 14 more than the smaller number. what are the numbers?

Answer 1

The numbers would be 41 and 27

Explanation:

It would be 41 and 27 because the number we know is 64 so if you divide that by 2 you have 34 (34+34=68) and if you then take half of 14 (14 comes from this part of the question "the larger number is 14 more than the smaller number".) (14/2=7) 7 from one side and add it to the other side you get 41+27=68

(we can also fact check this because your smaller number 27 plus 14 equal 41, then and 41 plus 27 equals 68)

Answer 2

• Let the smaller number be x.
• Then, the larger number = x + 14
• Given, the sum of these two numbers is 68.
• Therefore, by the problem
• x + (x + 14) = 68
• or, 2x + 14 = 68
• or, 2x = 68 - 14
• or, 2x = 54
• or, x = 54 ÷ 2
• or, x = 27
• Therefore, the smaller number is 27.
• So, the larger number = (27 + 14) = 41

Answer:

The numbers are 27 and 41.

Hope you could get an idea from here.

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