Question

A ball is thrown from an initial height of 3 feet with an initial upward velocity of 37 fts. The ball's height h (in feet) after 1 seconds is given by the following.

h= 3+37t-16t^2
Find all values of t for which the ball's height is 23 feet.

Answer 1

t=(37+root89)/32,(37-root89)/32

Explanation:

Solve the equation:

23=3+37t-16t^2