Answer:
False.
General Formulas and Concepts:
Algebra I
Terms/Coefficients
Calculus
Differentiation
- Derivatives
- Derivative Notation
Derivative Rule [Basic Power Rule]:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Derivative Rule [Product Rule]:
![\displaystyle (d)/(dx) [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)](https://img.qammunity.org/2022/formulas/mathematics/college/c6fshhoq1mws6w0d0la17c7k2dcytwd8kg.png)
Explanation:
Step 1: Define
Identify.
![\displaystyle (d)/(dx)[x^3e^x]](https://img.qammunity.org/2022/formulas/mathematics/high-school/i077w6p0svo4kjuc7apxh0hpbclyspb8kl.png)
Step 2: Differentiate
- Derivative Rule [Product Rule]:
![\displaystyle (d)/(dx)[x^3e^x] = (d)/(dx)[x^3]e^x + x^3 (d)/(dx)[e^x]](https://img.qammunity.org/2022/formulas/mathematics/high-school/nollzwwttwawm8zwmjq58v1x3bmq8vyoy0.png)
- Derivative Rule [Basic Power Rule]:
![\displaystyle (d)/(dx)[x^3e^x] = 3x^2e^x + x^3 (d)/(dx)[e^x]](https://img.qammunity.org/2022/formulas/mathematics/high-school/r6wznfnwmvd93yifpzu5hyxo8yrsytuoop.png)
- Exponential Differentiation:
![\displaystyle (d)/(dx)[x^3e^x] = 3x^2e^x + x^3e^x](https://img.qammunity.org/2022/formulas/mathematics/high-school/ctmludi5rx9auuxprinmainq1zevz6qits.png)
- Factor:
![\displaystyle (d)/(dx)[x^3e^x] = (x^3 + 3x^2)e^x](https://img.qammunity.org/2022/formulas/mathematics/high-school/g8imp6ogtaygbf4dc5mdq950l9ydq6hkrb.png)
∴
but
.
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation