Question

An object is released from height of 17m.
The object will hit the ground approximately in

Answer 1

`\text{Given that,}\\\\\text{Height, h = 17 m}\\\\\\\text{We know that,}\\\\h = v_0t + \frac 12 gt^2\\\\\implies h = \frac 12 gt^2\\\\\implies t^2 = \frac{2h}g\\\\\implies t =\sqrt{\frac{2h}g} = \sqrt{(2(17))/(9.81)} = 1.87 ~ \text{sec}`