Question

Hello people ~
factorise: 21x²+43-14​

Answer 1

`\\ \rm\rightarrowtail 21x^2+43x-14`

`\\ \rm\rightarrowtail 21x^2+49x-6x-14`

`\\ \rm\rightarrowtail 7x(3x+7)-2(3x+7)`

`\\ \rm\rightarrowtail (7x-2)(3x+7)`

Done!

Answer 2

`\displaystyle [7x - 2][3x + 7]`

Step-by-step Step-by-step explanation:

Find two quantities that when differed to 43, they also multiply to 294. Those will be 6 and 49. The TINIER quantity gets the minus symbol because the B-value is 43, therefore 49 gets the plus symbol, leaving 6 with the minus symbol. In extension, sinse we have a leading coefficient greater than one, we need to take extra procedures. Here is how it is done:

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